.01x^2+x-1100=0

Solution for .01x^2+x-1100=0 equation:

.01x^2+x-1100=0

a = .01; b = 1; c = -1100;
Δ = b2-4ac
Δ = 12-4·.01·(-1100)
Δ = 45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{45}=\sqrt{9*5}=\sqrt{9}*\sqrt{5}=3\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-3\sqrt{5}}{2*.01}=\frac{-1-3\sqrt{5}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+3\sqrt{5}}{2*.01}=\frac{-1+3\sqrt{5}}{0.02}
$